Question

Ma ajuta cineva????Va rog !!!​

Answer 1

Răspuns:

Explicație pas cu pas:

11. Conditii de existenta : x>0 => D=(0;+∞)

㏒₇x=0 =>x=$7^{0}$=1∈D

12. ㏒₂3-㏒₂6=㏒₂$\frac{3}{6}$=㏒₂$\frac{1}{2}$=㏒₂$2^{-1}$=-1*㏒₂2=-1∈Z

13. ㏒₂(㏒₃9)=㏒₂(㏒₃$3^{2}$)=㏒₂(2㏒₃3)=㏒₂2=1∈Z

14. Conditii de existenta : x>0 => D=(0;+∞)

㏒₂x=-1=>x=$2^{-1}=\frac{1}{2}$ ∈D

15.㏒₂4+㏒₂$\frac{1}{4}$=㏒₂(4*$\frac{1}{4}$)=㏒₂1=㏒₂$2^{0}$=0*㏒₂2=0*1=0