Question

ma ajuta si pe mine cineva la aceasta problema, chimie

Answer 1

CH3-CH(CH3)-CH(NH2)-CONH- [-CH(C3H7)-CONH-]n-CH(C3H7)-COOH
C(10+5n)H(21+10n)O(3+n)      M = 120+60n + 21+10n+48+16n= 189+86n
16(3+n)·100/(189+86n) = 16,425
64(3+n) = 124,173 + 56,502n      7,498n = 67,827    n = 9
⇒ 11 resturi de valina
2.  R-CH(NH2)-COONa
23·100/M = 15,032    M = 153g/mol 
mR = 153 - 96 = 57        R = -C4H9    aminoacid = leucina