Question

Ma ajuta si pe mn cineva
a) 3x-5 < x + 7
b) ( 3 x -6) (4 x- 3) < 0

Answer 1

$\displaystyle a) .3x-5 \ \textless \ x + 7 \\ 3x-x\ \textless \ 7+5 \\ 2x\ \textless \ 12 \\ x\ \textless \ \frac{12}{2} \\ x\ \textless \ 6$
$\displaystyle b) .( 3 x -6) (4 x- 3) \ \textless \ 0 \\ 3x-6\ \textless \ 0 \\ 3x\ \textless \ 0+6 \\ 3x\ \textless \ 6 \\ x\ \textless \ \frac{6}{3} \\ x\ \textless \ 2 \\ 4x-3\ \textless \ 0 \\ 4x\ \textless \ 0+3 \\ 4x\ \textless \ 3 \\ x\ \textless \ \frac{3}{4}$