Question

Mă ajutați la 3? Dau coroană.

Answer 1

$a) \frac{2x + 1}{5} \: echiunitara$

$2x + 1 = 5$

$2x = 5 - 1$

$2x = 4$

$x = \frac{4}{2}$

$x = 2$

$b) \frac{12 - 3x}{3} \: echiunitara$

$12 - 3x = 3$

$- 3x = 3 - 12$

$- 3x = - 9 \: | \div ( - 3)$

$x = 3$

$c) \frac{18 \div x - 1}{2} \: echiunitara$

$18 \div x - 1 = 2 \: | \times x$

$18 - x= 2x$

$- x - 2x = - 18$

$- 3x = - 18 \: | \div ( - 3)$

$x = 6$

$d) \frac{x \div 5 + 18}{43} \: echiunitara$

$x \div 5 + 18 = 43 \: | \times 5$

$x + 90 = 215$

$x = 215 - 90$

$x = 125$

$e) \frac{[(123 - x) \times 3 + 5] \div 2}{19} \: echiunitara$

$[(123 - x) \times 3 + 5] \div 2 = 19 \: | \times 2$

$(123 -x ) \times 3 + 5 = 38$

$(123 - x) \times 3 = 38 - 5$

$(123 - x) \times 3 = 33 \: | \div 3$

$123 - x = 11$

$- x = 11 - 123$

$- x = - 112 \: | \times ( - 1)$

$x = 112$

$f) \frac{175 - [(x \div 7 + 8) \div 3 + 40] \div 9}{4 \times 20 + 30 \times 3} \: echiunitara$

$175 - [(x \div 7 + 8) \div 3 + 40] \div 9 = 4 \times 20 + 30 \times 3$

$175 - [(x \div 7 + 8) \div 3 + 40] \div 9 = 80 + 90$

$175 - [(x \div 7 + 8) \div 3 + 40] \div 9 = 170$

$- [(x \div 7 + 8) \div 3 + 40] \div 9 = 170 - 175$

$- [(x \div 7 + 8) \div 3 + 40] \div 9 = - 5 \: | \times ( - 1)$

$[(x \div 7 + 8) \div 3 + 40] \div 9 = 5 \: | \times 9$

$(x \div 7 + 8) \div 3 + 40 = 45$

$(x \div 7 + 8) \div 3 = 45 - 40$

$(x \div 7 + 8) \div 3 = 5 \: | \times 3$

$x \div 7 + 8 = 15$

$x \div 7 = 15 - 8$

$x \div 7 = 7$

$x = 7 \times 7$

$x = 49$