Question

ma ajutati la acest exercitiu??

Answer 1

a)(x+√3)²-(2√3)²=(x+√3-2√3)(x+√3+2√3)=(x-√3)(x+3√3)
b)(y-√2)²-(2√2)²=(y-√2-2√2)(y-√2+2√2)=(y-3√2)(y+√2)
d)(2x+√5)²-45=(2x+√5)²-(3√5)²=(2x+√5-3√5)(2x+√5+3√5)=(2x-2√5)(2x+4√5)
e)27x²-(1-√3x)²=(3√3x)²-(1-√3x)²=(3√3x-1+√3x)(3√3x+1-√3x)=(4√3x-1)(2√3x+1)
g)(x+√3)²-(2x+2√3)²=(x+√3-2x-2√3)(x+√3+2x+2√3)=(-x-√3)(3x+3√3)
h)8x²-(√2x+1)²=(2√2x)²-(√2x+1)²=(2√2x-√2x-1)(2√2x+√2x+1)=(√2x-1)(3√2x+1)
j)$(2x+ \frac{1}{4}) ^{2}-(x- \frac{3}{4}) ^{2}=(2x+ \frac{1}{4} -x+ \frac{3}{4})(2x+ \frac{1}{4} +x- \frac{3}{4})=$
=$(x+1)(3x- \frac{1}{2})$
k)$(3-x) ^{2} -( \frac{3}{2}) ^{2}=(3-x- \frac{3}{2} )(3-x+ \frac{3}{2})=[tex](-x+\frac{6}{2} - \frac{3}{2})(-x+ \frac{6}{2}+ \frac{3}{2})=(-x+ \frac{3}{2} )(-x+ \frac{9}{2} )$