Question

Ma ajutati la exercitiul 9 va rog?​

Answer 1

Răspuns:

a = 2^7•3^8+2^9•3^7+2^7•3^8

a = 2^7•3^7•(3+2²•1+1•3)

a = (2•3)^7•(3+4+3)

a = 6^7•10

a = 6^7•2•5 → divizibil cu 5.

EVERGREEN

Answer 2

Răspuns: Ai demonstrația mai jos

Explicație pas cu pas:

$\bf a = 2^7\cdot3^8+2^9\cdot3^7+2^7\cdot3^8$

$\bf a = 2^7\cdot3^7\cdot\Big(2^{7-7}\cdot3^{8-7}+2^{9-7}\cdot3^{7-7}+2^{7-7}\cdot3^{8-7}\Big)$

$\bf a = 2^7\cdot3^7\cdot\Big(2^{0}\cdot3^{1}+2^{2}\cdot3^{0}+2^{0}\cdot3^{1}\Big)$

$\bf a = 2^7\cdot3^7\cdot\Big(1\cdot3+4\cdot1+1\cdot3\Big)$

$\bf a = 2^7\cdot3^7\cdot\Big(3+4+3\Big)$

$\bf a = 2^7\cdot3^7\cdot 10$

$\bf a = 2^7\cdot3^7\cdot 2\cdot 5$

$\bf a = 2^{7+1}\cdot3^7\cdot 5$

$\red{\boxed{~\bf a = 2^{8}\cdot3^7\cdot 5\implies ~a~~\vdots~~5~ }}$

$==pav38==$