Question

Ma ajutati si oe mine va rog

Answer 1

a) notam cu x latura patratului
BQ = PC = (60-x)/2
calculam inaltimea AD cu pitagora
AD^2 = AB^2-BD^2 = 50^2-30^2
AD = 40
tr. BMQ si BAD sunt asemenea
x/AD = BQ/BD
x/40 = [(60-x)/2]/30
x = 24
b) aria ABC = A
A = BC*AD/2
A = 60*40/2
A = 1200 cm2
c) aria patrat = 24^2 = 576 cm2
A/2 = 600
600 > 576