Question

Ma ajutati si pe mine la ex. 19 doar subpunctul a va roooooog

Answer 1

[tex]\displaystyleE(x)=( \frac{x-6}{(x-5)(x+5)} + ^{x+5)}\frac{x}{x-5}-^{x-5)} \frac{2}{x+5} )\cdot \frac{(x-5)(x+5)}{2x^2-3x+4x-6} \\ E(x)= \frac{x-6+x^2+5x-2x+10}{(x-5)(x+5)}\cdot \frac{(x-5)(x+5)}{x(2x-3)+2(2x-3)}\\ E(x)= \frac{(x+2)^2}{(x-5)(x+5)} \cdot \frac{(x-5)(x+5)}{(2x-3)(x+2)}\\ E(x)= \frac{x+2}{2x-3} [/tex]