Question

ma ajutati si pe mine va rog frumos?

Answer 1

$\lim_{x \to \0} \frac{sin^{2}2x}{5 x^{2} }= \lim_{x \to \0} ( \frac{sin2x}{2x} )^{2}* \frac{4 x^{2} }{5 x^{2} }= \lim_{x \to \0} 1^{2}* \frac{4}{5} = \frac{4}{5}$