Question

Ma ajutati si pe mn va rog cu exercitiul 6?

Answer 1

$\it [AE-bisectoare\ pentru\ \widehat{BAC} \Rightarrow \widehat{BAC}=2\cdot\widehat{CAE}=2\cdot35^o=70^o\\ \\ \Delta ABC-isoscel,\ AB=BC\Rightarrow \widehat{BCA}=\widehat{BAC}=70^o\\ \\ \widehat{AEB}\ este\ unghi\ exterior\ pentru\ \Delta AEC \Rightarrow \widehat{AEB}=70^o+35^o=105^o$