Question

Ma ajutati?Va rog??????

Answer 1

a) =$\frac{2x}{x-3} - \frac{3}{x-3} - \frac{x}{x-3} =$

=$\frac{2x-x-3}{x-3}$=

=$\frac{x-3}{x-3}$=1

b) =$\frac{a+1}{ a^{2} -1}$=

=$\frac{a+1}{(a+1)(a-1)}$=

=$\frac{1}{a-1}$=

c) $\frac{4 p^{2} +9}{(3+2p)(3-2p)} + \frac{2p(3-2p)}{(3+2p)(3-2p)} + \frac{5(3+2p)}{(3+2p)(3-2p)}$=

=$\frac{4 p^{2} +9+6p-4 p^{2} +15+10p}{(3+2p)(3-2p)}$=

=$\frac{24+16p}{(3+2p)(3-2p)}$=

=$\frac{8(3+2p)}{(3+2p)(3-2p)}$=

=$\frac{8}{3-2p}$