Question

Ma ajutati va rog cat mai repede posibil.

Answer 1

2. nCa = 6 moli

3Ca + 2H3PO4 -> Ca3(PO4)2 + 3H2

3 moli Ca..................2 moli H3PO4
6 moli Ca..................x moli H3PO4

x=2*6/3 = Calculeaza !!

3. V=44,8L Cl2

n=V/Vm = 44,8/22,4 = 2 moli Cl2

H2 + Cl2 -> 2HCl

1 mol Cl2..................2*36,5g HCl
2 moli Cl2....................x=146g HCl


4. m Al = 5,4g ,   MAl=27g/mol

n=m/M=5,4/27 = 0,2 moli Al

2Al + 6HCl -> AlCl3 + 3H2

2 moli Al...................6 moli HCl
0,2 moli Al...............x=0,6 moli HCl

2 moli Al..........................133,5g AlCl3
0,2 moli Al........................x=13,35g AlCl3

MAlCl3=AAl+3ACl = 27+3*35,5=133,5g/mol

5. nr molecule = 12,044*10^24 N2 = 120,44*10^23 molecule N2

1 mol N2.......................6,022*10^23 molecule
x moli N2......................120,44*10^23 molecule

x=120,44/6,022 = 20 moli N2

N2 + 3H2 -> 2NH3

1 mol N2.................3 moli H2
20 moli N2.............x=3*20 = 60 moli H2