Question

ma ajutati va rog cu cele 2 exerciti

Answer 1

In locul casuteti goale poti pune x si obtii:

b) $\frac{5}{9}-\frac{3}{2} =\frac{7}{3}+x$

Aducem la acelasi numitor, numitorul comun va fi 9x2=18

$\frac{5*2}{9*2}-\frac{3*9}{2*9}=\frac{7*6}{3*6}+\frac{x*18}{18}$

$\frac{10}{18}-\frac{27}{18}=\frac{42}{18}+\frac{18x}{18}$

Am obtinut acelasi numitor, deci vom renunta la el.

$10-27=42+18x$

$-17=42+18x$

$18x=-17-42$

$18x=-59$

$x=-\frac{59}{18}$

d) Cunoastem $\frac{2}{5} = 0,4$

-9,83+x=13+0,4

-9,83+x=13,4

Grupam termenii liberi, tinem cont ca ce trece dupa egal isi schimba semnul:

x=13,4+9,83

x=23,23