Question

Ma ajutati va rog si la asta? :(

Answer 1

3,(3)=30/9=10/3
2,(6)=24/9=8/3
0,(36)=36/99=12/33
0,(12)=12/99=4/33
luand in considerare toate acestea:
[3,(3)-2,(6)-0,(36)]:0,(12)=(10/3-8/3-12/33):4/33=(2/3-12/33)*33/4=(22/33-12/33)*33/4=10/33*33/4=10/4=5/2=2,5

Answer 2

d)
= [(33-3)/9 - (26-2)/9 - 36 /99]:12/99=
=(30/9 - 24/ 9-36/99):12/99=
=(10/3 - 8 /3 - 4/ 11):4/33=
Numitorul comun al numerelor(3, 11) este 33 si amplificam cu 11, respecti 3
=(110/33 - 88/ 33-12/33) :4/33=
=10/33 x 33/4=
=5/2=
=2 intregi si 1/2
sau =2,5