Question

Mă poate ajuta cineva? ​

Answer 1

Răspuns:

a. 3^12/3^10+(3*5)^10/15^9-2011^0*1^2021=

3^12-10+15^10/15^9-1=

3^2+15^10-9-1=

9+15^1-1=

9+15-1=

24-1=23

b. 4^13/8^6+7^3-5^2*(625:5^4+16/(7*3^2-55))=

(2^2)^13/(2^3)^6+343-25*(625/625+16/(7*9-55))=

2^2*13/2^3*6+343-25*(1+16/(63-55))=

2^26/2^18+343-25*(1+16/8)=

2^26-18+343-25*(1+2)=

2^8+343-25*3=

256+343-75=

599-75=524

c. 18*(1+3^7*3^53+7^84/7^14+(5^4)^20)/(13^0+3^60+7^70+5^80)=

18*(1+3^7+53+7^84-14+5^4*20)/(1+3^60+7^70+5^80)=

18*(1+3^60+7^70+5^80)/(1+3^60+7^70+5^80)=

18*1=18

Sper ca te-am ajutat! ^^

Answer 2

Răspuns punctul a si punctul b