Question

Ma poate ajuta cineva? ​

Answer 1

a) 2/√45[1/(1/2√5-1/√45)•(1/√5-√3-√3/2] =

= 2/3√5 (amplificam cu √5) (6√5• √5/2) = ====>

1/(1/2√5 (amplificam cu √5) - 1/√45) =

= 1/(1/2√5/5-1/3√5 (amplificam cu √5) =

= 1/(√5/10(amplificam cu 3)-√5/15(amplificam cu 2) =

= 1/(3√5-2√5/30) = 1/√5/30=1:√5/30=1•30/√5 =

= 30/√5 (amplificam cu √5) = 30√5/5 = 6√5

(1/√5-√3(amplificam cu √5+√3)-√3/2) =

= √5+√3/5-3-√3/2 = √5+√3/2-√3/2 = √5/2

====> = 2√5/15 (6•5/2) = 2√5/15•(3•5) =

= 2√5/15•15 = 2√5

===> 2√5