Question

Ma poate ajuta cineva am nevoie urgent
Functii derivabile

Answer 1

Răspuns:

Explicație pas cu pas:

1.f'(x)=3x²+3^x·ln3

2. f'(x)=4x³+14x+21

3. f'(x)=5cosx+7sinx

4. f'(x)=1+1/x

5. f'(x)=√x+x/2√x+∛x+x/3∛x²=√x+√x/2+∛x+x∛x/3x=3√x/2+4∛x/3

6. f'(x)=lnx+x×1/x=lnx+1

9. f'(x)=cos²x-sin²x

10. f'(x)=sinx×e^x+cosx×e^x

13. f'(x)=(1/x×x-lnx)/x²=(1-lnx)/x²

14/ f'(x)=-1(x²+1)²×2x=-2x/(x²+1)²

16.f'(x)=1/cos²x

17. f'(x)=-1/sin²x