Ma poate ajuta cineva cu aceste calcule?
Răspunsuri la întrebare
Răspuns:
a) 16-3×[(21-2×9÷3)÷3-1]=
16-3×[(21-18÷3)÷3-1]=
16-3×[(21-6)÷3-1]=
16-3×(15÷3-1)=
16-3×(5-1)=
16-3×4=
16-12=4
b)45-36÷[90÷(8-5)-8×(3×13-9×4 )]=
45-36÷[90÷3-8×(39-36)]=
45-36÷(90÷3-8×3)=
45-36÷(30-24)=
45-36÷6=
45-6=39
c) 2×4-4×{3+3×[16+2×2×(8+2)]÷2÷3}÷31=
2×4-4×[3+3×(16+2×2×10)÷2÷3]÷31=
2×4-4×[3+3×(16+40)÷2÷3]÷31=
2×4-4×(3+3×56÷2÷3)÷31=
2×4-4×(3+168÷2÷3)÷31=
2×4-4×(3+84÷3)÷31=
2×4-4×(3+28)÷31=
2×4-4×31÷31=
8-124÷31=
8-4=4
d)24-3×[(7×3-2×9÷3)÷3-1]=
24-3×[(21-18÷3)÷3-1]=
24-3×[(21-6)÷3-1]=
24-3×(15÷3-1)=
24-3×(5-1)=
24-3×4=
24-12=12
e) 10-10÷{1+3×[(57-15×2)÷3+21]÷10}=
10-10÷{1+3×[(57-30)÷3+21]÷10}=
10-10÷[1+3×(27÷3+21)÷10]=
10-10÷[1+3×(9+21)÷10]=
10-10÷(1+3×30÷10)=
10-10÷(1+90÷10)=
10-10÷(1+9)=
10-10÷10=
10-1= 9
f) 113-3×{56-2×1×[18+3×(6+21)]÷9}=
113-3×[56-2×1×(18+3×27)÷9]=
113-3×[56-2×1×(18+81)÷9]=
113-3×(56-2×1×99÷9)=
113-3×(56-2×11)=
113-3×(56-22)=
113-3×34=
113-102=11