Question

ma poate ajuta cineva cu aceste exercitii​

Answer 1

Răspuns:

521=10x1-0+n

521=10+n

521-10=n

511=n

4+[4-(4+4:4x4-4)+a]:4=8

4+[4-(4+1x4-4)+a]:4=8

4+[4-(4+4-4)+a]:4=8

4+[4-(8-4)+a]:4=8

4+[4-4+a]:4=8

(4-4+a):4=8-4

(4-4+a):4=4

4-4+a=4x4

4-4+a=16

a=16-4+4

a=16-0

a=16

b:6x6:3x3=8+8+9:9+13

b:6x2x3=16+1+13

b:6x6=17+13

b:6x6=30

b:6=30:6

b:6=5

b=5x6

b=30

113+(113x8)=2000-y+y:y

113+904=2000-y+1

y=2000-113-904+1

y=984

(h:5-5)x9+186:6=400:10

(h:5-5)x9+31=40

(h:5-5)x9=40-31

(h:5-5)x9=9

h:5-5=9:9

h:5-5=1

h:5=1+5

h:5=6

h=6x5

h=30

8+6x[4+27:(0+ux9)]=49+10:10

8+6x[4+27:(0+ux9)]=49+1

8+6x[4+27:(0+ux9)]=50

6x[4+27:(0+ux9)]=50-8

6x[4+27:(0+ux9)]=42

4+27:(0+ux9)=42:6

4+27:(0+ux9)=7

27:(0+ux9)=7-4

27:(0+ux9)=3

0+ux9=27:3

ux9=9

u=9:9

u=1

[12-9:3+(12-9):3]xz+1=41

[12-3+3:3]xz=41

(12-3+1)xz=41

10xz=41

z=41:10

z=4,1

Explicație pas cu pas: