Question

ma poate ajuta cineva cu aceste exercitii va rog 9×[19×(9×19-19×9)÷9]+(9÷9)+19= ;[2×(12×5-5×6)×2-2×2×5]÷10-729÷9÷9= ; 2×[2+2×(2×22-20)]÷10+(222÷2-22)+1= ; [12+12×(12÷2)÷9]÷(20-2×2×2-2)= ; [(136÷4-29)÷(2+27÷9)]×(7+7×7)= ; 555-5×[5+5×(5+5×0)-(5×5)]×5= ; 5+5×[50+(5-5÷5)-(55-5×9)]÷4= ; [11-(6+6×6-6÷6+6×6)÷7]×6= ; [(7+7)×(7-7)÷(7+7)×7]×7+7= ; 8+[8×(8-8÷8)+8]×8-(8+412÷4)= ; 9×(42÷7)×4-(180-72)]÷3-36=​

Answer 1

Răspuns:

9x[19x(9x19-19x9):9]+(9:9)+19=

9x[19x(171-171):9]+1+19=

9x(19x0:9)+1+19=

9x(0:9)+1+19=

9x0+1+19=

0+1+19=20

[2x(12x5-5x6)x2-2x2x5]:10-729:9:9=

[2x(60-30)x2-4x5]:10-81:9

(2x30x2-20):10-9

(60x2-20):10-9

(120-20):10-9

100:10-9

10-9=1

2×[2+2×(2×22-20)]÷10+(222÷2-22)+1=

2x[2+2x(44-20)]:10+(111-22)+1

2x(2+2x24):10+89+1

2x(2+48):10+89+1

2x50:10+89+1

100:10+89+1

10+89+1=

99+1=100

[12+12×(12÷2)÷9]÷(20-2×2×2-2)=

(12+12x6:9):(20-4x2-2)

(12+72:9):(20-8-2)

(12+8):(12-2)

20:10=2

[(136÷4-29)÷(2+27÷9)]×(7+7×7)=

[(34-29):(2+3)]x(7+49)

(5:5)x56

1x56=56

555-5×[5+5×(5+5×0)-(5×5)]×5=

555-5x[5+5x(5+0)-25]x5

555-5x(5+5x5-25)x5

555-5x(5+25-25)x5

555-5x5x5

555-25x5

555-125=430

5+5×[50+(5-5÷5)-(55-5×9)]÷4=

5+5x[50+(5-1)-(55-45)]:4

5+5x(50+4-10):4

5+5x(54-10):4

5+5x44:4

5+220:4

5+55=60

[11-(6+6×6-6÷6+6×6)÷7]×6=

[11-(6+36-1+36):7]X6

[11-(42-1+36):7]X6

[11-(41+36):7]X6

(11-77:7)X6

(11-11)X6

0x6=0

[(7+7)×(7-7)÷(7+7)×7]×7+7= ;

(14x0:14x7)x7+7

(0:14x7)x7+7

0x7+7

0+7=7

8+[8×(8-8÷8)+8]×8-(8+412÷4)=

8+[8x(8-1)+8]x8-(8+103)

8+(8x7+8)x8-111

8+(56+8)x8-111

8+64x8-111

8+512-111

520-111= 409

[9×(42÷7)×4-(180-72)]÷3-36=

(9x6x4-108):3-36

(54x4-108):3-36

(216-108):3-36

108:3-36

36:36=1