Question

ma poate ajuta cineva cu asta ?

Answer 1

Răspuns:

c =(√200+√150)/5√2=

15·√(200/2)+1/5·(150/2)=

1/5·√100+1/5·√75=

1/5·10+1/5·5√3=2+√3

d = [(√3(√6-2)+(√6+√12)/√3]/2-√8=

[(√3(√6-2)+(√6/3+√12/3)]/2-√8=

[√3(√6-2)+√2+2]/2=√8=

[√18-2√3+√2+2]/2-√8=

(3√2-2√3+√2+2)/2-√8=

(4√2-2√3+2)/2-√8=

[2(√2-√3+1)]/2-2√2=

2√2-√3+1-2√2=1-√3

c+d=2+√3+1-√3=3 ∈ N