Question

Ma poate ajuta cineva, cu o problema la chimie clasa a 11 a

Answer 1

4mol.....................4mol
CH4 + CL2----> CH3Cl+HCl
2mol....................2mol
CH4 + 2Cl2--> CH2Cl2 +2HCl
1mol...................1mol
CH4 +3Cl2---> CHCl3 +3HCl
1mol..........................1mol
CH4---------------------->CH4
n,total CH4= 8 mol
Cu= n,CH4 transformat in prima reactiex100/n,total= 400/8=50%
Ct= n,CH4 transformat in toate reactiile x100/n,total= 7x100/8=87,5%
randament = Cux100/Ct= .................calculeaza!!!!!



n,CH3cL= m/M= 404kg/50,5kg/kmol= 8kmol


din reactiile de mai sus am dedus ca:  4kmol CH3Cl se obtin din 8kmolCH4
                                                              8kmol...........................n= 16kmol
V= nxVm= 16kmolx22,4 mcub/kmol=..........................calculeaza !!!!!