Question

Ma poate ajuta cineva? doar ex2...

Answer 1

2. a) C=0.2 M HCl
n= 0.15 moli NaOH
Cm=n/Vs => Vs= n/Cm=0.15/0.2=0,75 L
b)m=2.24g Koh
MKOH=39+16+1=56g/mol
n=m/M=2.24/56=0.04 moli
Cm=n/Vs =>Vs=n/Cm=0.04/0.2=0.2L
c)Cm=n/Vs=>n=Cm*Vs=0.02*0.01=0.02 moli
Cm=n/Vs => Vs=n/Cm=0.02/0.2=0.1L
d) 40/18=20/1 => 40=20*18 =9 g
Cm=md/M*Vs => Vs=md/Cm*M = 9/0.2*40=1.125L