Question

ma poate ajuta cineva ???
e urgeeeent !!!!

Answer 1

3600·(100-p)/100·(100-p)/100=2601

36·(100-p)²=260100

(100-p)²=260100÷36

(100-p)²=7225

100-p=√7225

100-p=85 ⇒p=100-85 ⇒ p=15 %

Deci telefonul a fost redus cu 15% de fiecare data !

Answer 2

$(3600\cdot\frac{p}{100})\cdot\frac{p}{100}=2601\\\\(\frac{p}{100})^2=\frac{2601}{3600}=\frac{7225}{10^2}\;\;\Rightarrow\;\;p=\sqrt{7225}=85\\\\inseamna\;ca\;procentul\;de\;reducere,a\;fost\;de\;100^o/_o-85^o/_o=15^o/_o$