Question

Ma poate ajuta cineva? E urgent

Answer 1

asta este...................

Answer 2

$\frac{x^2-4}{x^2+2x} + \frac{2}{x} = \frac{(x-2)(x+2)}{x(x+2)} + \frac{2}{x} = \\ \\ = \frac{x-2}{x} + \frac{2}{x} = \frac{x-2+2}{x} = \\ \\ \frac{x}{x} =1$