Question

Ma poate ajuta cineva la 10 si 11
Va rog, cat mai repede!
Dau coroana la cel mai bun (ambele exercitii)

Answer 1

[tex]10.\\\\ E(x)=( \frac{3x+2}{x+3} -2): \frac{2x-8}{3x+9} \\\\ E(x)= \frac{3x+2-[2(x+3)]}{x+3} :\frac{2x-8}{3x+9}\\\\ E(x)= \frac{3x+2-2x-6}{x+3} * \frac{3(x+3)}{2(x-4)} \\\\ E(x)= \frac{x-4}{x+3} * \frac{3(x+3)}{2(x-4)} \\\\ E(x)= \frac{3}{2} =\ \textgreater \ expresia~este~constanta.[/tex]

[tex]11.\\\\ E(x)=( \frac{1}{x}- \frac{1}{x+1} ): \frac{2x+6}{x^2+3x} \\\\ E(x)= \frac{x+1-x}{x(x+1)} * \frac{x(x+3)}{2(x+3)} \\\\ E(x)= \frac{1}{2(x+1)} [/tex]