Question

ma poate ajuta cineva la 32???​

Answer 1

Răspuns:

Explicație pas cu pas:

E(x)=[x²/(x⁴+x³)]:[(2x+1)·(x-1)-x·(x-1)]/[(x+1)·(2x-2)]=

[x²/x²(x²+x)]·[(x+1)·(2x-2)]/[(2x+1)·(x-1)-x·(x-1)]=

[1/(x²+x)]·[2·(x+1)·(x-1)]/[(x-1)·(2x+1-x)]=[1/x(x+1)]·[2·(x+1)·(x-1)]/[(x-1)·(x+1)]=

[1/x(x+1)]·[2·(x-1)]/[(x-1)]=[1/x(x+1)]·2=2/x(x+1)    ∀ x∈R\{-1; 1; 0}