Question

Ma poate ajuta cineva la aceste exerciții? Mulțumesc anticipat

Answer 1

a) ( 4√2 - √30 )( 4√2 + √30) - 3(√5+1)² =
= 16 × 2 - 30 - 3(5+2√5+1) =
= 32 - 30 - 3(6+2√5) =
= 32 - 30 - 18 - 6√5 = -16 - 6√5 

b) 4(3+1)²-√3*(8-√3)-(√21-√2)(√21+√2) =
= 4(3+2√3+1)-8√3+3-(21-2) =
= 4(4+2√3)-8√3+3-19 =
= 16 + 8√3 - 8√3 + 3 - 19 = 0

c) ( 3√5 - 1)² + √180 - ( 2√3 - √5)(2√3 + √5) =
= 45 - 6√5 + 1 + 6√5 - (4*3-5) =
= 45 + 1 -( 12-5) =
= 45 + 1 - 7 = 39

d) ( √14 + 3)² + ( √7 - 3√2)² - (√15-√7)(√15+√7) -
= 14 + 6 √14 + 9 + 7 - 6√14 + 18 - ( -15 - 7 ) =
= 14 + 9 + 7 + 18 - 8 = 40

e) ( √6 - 2)²+2(1+√6)² + ( √6-2)(√6+2) =
= 6 - 4√6 + 4 + 2(1+2√6+6)+6-4 =
= 6 - 4√6 + 4 + 2(7+2√6)+6-4 =
= 6 - 4√6 + 4 + 14 + 4√6 + 6 - 4 = 26

f) 2(3√3+1)²+3(√3-2)²-(11-√15)(11+√15) =
= 2(27 + 6√3 + 1)+3(3-4√3+4)-(121-15) =
= 2(28 + 6√3)+3(7-4√3)-106 =
= 56 + 12√3 + 21 - 12√3 - 106 = -29