Question

Ma poate ajuta cineva la problema 7?

Answer 1

Zn + 2 HCl = ZnCl2 + H2
V c.n. = 22.4 l
M Zn = 65 g/mol
65 g Zn.........22,4 l H2
x..................44,8 l H2
x = 130 g Zn
m Cu = m aliaj -  m Zn = 200-130 = 70 g
%Cu = m Cu/m aliaj * 100 = 70/200 * 100 = 35%
%Zn = mZn/m aliaj * 100 = 130/200 * 100 = 65%