Question

ma poate ajuta cineva ? va rog

Answer 1

Răspuns

Explicație pas cu pas:

f = 1 + √3 + √2 x + (1 + √2)x^2

g = √3 x  + (1 + √3)x^2

f + g = x^2 (1 + √2 + 1 + √3) + x (√2 + √3) + 1 + √3 = x^2 (2 + √2 + √3) + x (√2 + √3) + 1 + √3

f*g = [1 + √3 + √2 x + (1 + √2)x^2 ] * [√3 x  + (1 + √3)x^2] =

= √3 x + 3x + √6x^2 + √3(1 + √2)x^3 + (1 + √3)x^2 + √3(1 + √3)x^2 + √2 (1 + √3) x^3 +  (1 + √2)(1 + √3)x^4

(1 + √2)(1 + √3) = 1 + √3 + √2 + √6

x^4 (1 + √3 + √2 + √6) + x^3 (√3 + 2√6 + √2) + x^2 (√6 + 4 + 2√3) + x (3 + √3)

_______________

f = ix - 3ix^2 + 2x^3

g = i - (1 + i)x + 3ix^3

f + g = x^3 (2 + 3i) - 3ix^2 + x (i - 1 - i) + i = x^3 (2 + 3i) - 3ix^2 - x + i

________

f*g = (ix - 3ix^2 + 2x^3) * [i - (1 + i)x + 3ix^3] =

ix - 3i^2x^2 + 2ix^3 - (1 + i)x^2 + 3i(1 + i)x^3 - 2(1 + i)x^3 + 3i^2x^4 - 9i^2x^5 + 6ix^6 =

= 6ix^6 - 9i^2x^5 + 3i^2x^4 + x^3(3i + 3i^2 - 2) + x^2(3i^2 - 1 - i)