Question

Ma poate ajuta cineva va rog dau coroana la primul raspuns ​

Answer 1

Răspuns:

M,MgO=40g/mol

M,o2=32g/mol

2x40g.......................32g

2MgO-------> 2Mg + O2

240g....................................x

x=m=96gO2

p=80%

p=m,px100/m,i---> m,p=80x150/100g=120g C pur

M,C=12g/mol

M,CO2=44g/mol

12g..............................44g

C   +   O2--------> CO2

120g.................................x

x=m=440gCO2 (10moli)

Explicație: