Question

Ma poate ajuta cineva, va rog? Dau coroana si 15 puncte <3. ​

Answer 1

Răspuns:

Explicație pas cu pas:

a)

4^37 = (2^2)^37 = 2^74

2^72 < 4^37

b)

100^10 = (10^2)^10 = 10^20

10^100 < 100^10

c)

9^30 = (3^2)^30 = 3^60

27^10 = (3^3)^10 = 3^30

9^30 > 27^10

d)

32^20 = (2^5)^20 = 2^100

16^25 = (2^4)^25 = 2^100

32^20 = 16^25

e)

81^20 = (9^2)^20 = 9^40

9^40 = 81^20

f)

3^45 = (3^3)^15 = 27^15

2^30 = (2^2)^15 = 4^15

3^45 > 2^30

g)

6^120 = (6^3)^40 = 216^40

5^80 = (5^2)^40 = 25^40

6^120 > 5^80

h)

200^30 = (2*100)^30 = 2^30*100^30 = 2^30*(10^2)^30 = 2^30*10^60

8^10*10^60 = (2^3)^10*10^60 = 2^30*10^60

200^30 = 8^10*10^60

i)

3^55 = (3^5)^11 = 243^11

2^88 = (2^8)^11 = 256^11

3^55 < 2^88