ma poate ajuta cnv la ex 10? va rog??e urgent!! dau 50 de puncte
Răspunsuri la întrebare
Răspuns:
a)F(x) nu e definita in punctele in care numitorul e 0
x-1=0=> x=1
x+1=0 x= -1
x²-1=0 (x-1)(x+1)=0 x1=1 x2=-1
x={-1,1}
b)Gx=(x+1)[2/(x-1)+1/(x+1)-2(x+1)/(x²-1)]
Gx=2(x+1)/(x-1)+(x+1)/(x+1)-2(x+1)²/(x-1)(x+1)
G(x)=2(x+1)/(x-1)+1-2(x+1)/(x-1)=1
c)Suma are 2016-1=2015 termeni
F(2)=1 f(3)=1
f(2)*F(3)=1*1=1
F(3)=1 f(4)=1
F(3)*F(4)=1
---------------------------------
F(2016)=1 F(2017)=1
F(2016)*F(2017)=1*1=1
Suma devine
1+1+...+1=2015*1=2015
Explicație pas cu pas:
Răspuns:
a)F(x) nu e definita daca numitorul este 0.
x-1=0=> x=1;
x+1=0 x= -1;
x²-1=0 (x-1)(x+1)=0 x1=1 x2=-1;
x={-1,1}
b)Gx=(x+1)[2/(x-1)+1/(x+1)-2(x+1)/(x²-1)]
Gx=2(x+1)/(x-1)+(x+1)/(x+1)-2(x+1)²/(x-1)(x+1)
G(x)=2(x+1)/(x-1)+1-2(x+1)/(x-1)=1
c)Suma are 2016-1=2015 termeni
F(2)=1 f(3)=1;
f(2)*F(3)=1*1=1;
F(3)=1 f(4)=1;
F(3)*F(4)=1;
F(2016)=1 F(2017)=1;
F(2016)*F(2017)=1*1=1;
1+1+...+1=2015*1=2015;