Question

Ma poate ajuta cu tot cineva ?

Answer 1

$1. \\ a) \sqrt{144} = 12 \\ b) \sqrt{1 + 3 + 5 + 7 + 9} = \sqrt{25} = > 5 \\ c) \sqrt{2} \times \sqrt{11} = \sqrt{22} \\ d) \sqrt{78} \div \sqrt{2} = \sqrt{39} \\ e) \sqrt{ \frac{900}{121} } = \frac{30}{11} \\ f) \sqrt{10 {}^{2} - 6 {}^{2} } = 8 \\ g) \sqrt{( - 10) {}^{6} } = 10 {}^{3} \\ h) | \sqrt{7} - 9| = 9 - \sqrt{7}$

$2. \\a) \sqrt{300 } = 10 \sqrt{3} \\ b) \sqrt{12}$

$3. \\ (2 \sqrt{3}) {}^{2} = 12 \\ (5 \sqrt{2} ) {}^{2} = 50 \\ 5 \sqrt{2} > 2 \sqrt{3}$

$4. \\ mg = \sqrt{(2 \times 8)} = \sqrt{16} = 4$

$6. \\ a = ( \sqrt{48} - 6 \sqrt{3} + \sqrt{108} - 2 \sqrt{3} + \frac{6}{ \sqrt{3} } ) \times 3 \\ \\ a = \sqrt{48} - 6 \sqrt{3} + \sqrt{108} - 2 \sqrt{3} + 6 \sqrt{3} \\ \\ a = 4 \sqrt{3} + 6 \sqrt{3} - 2 \sqrt{3} \\ \\ a = 8 \sqrt{3}$