Question

Ma poate ajuta si pe mine cineva?

Answer 1

1)
a) HC≡CH + 2 H2/Ni => CH3-CH3
b) HC≡CH + HCl / HgCl2 => CH2=CH-Cl
2.
a) HC≡CH + Cl2 => Cl-CH=CH-Cl
b) HC≡CH + H2O/ HgSO4/acid => CH2=CH-OH =tautomerizare => CH3-CHO
3. 
n CH2=CH-Cl => -(CH2-CH-Cl)- de n ori
4. atomi de C tertiati

5.
 $C_{n}H_{2n-2} +2 H_2=\ \textgreater \ C_nH_{2n+2}$
M alchina =54g/mol
$C_{n} H_{2n+2} = 54g/mol$
12n+2n-2 = 54
14n-2 = 54 
14n=54 + 2 
14n=56 => n= 4
Alchina A = butina CH≡CH-CH2-CH3  sau CH3-C≡C-CH3

6.
CH3-C≡C-CH3 + Cl2 => CH3-(Cl)C=C(Cl)-CH3

7. 
CaC2 + 2H2O=> C2H2 + Ca(OH)2
n CaC2 = 4 mol
1 mol CaC2 ...1 mol C2H2
4 mol CaC2 .... x
x=4 mol C2H2
V C2H2 = 22.4l/mol * n C2H2
V C2H2= 22.4 l/mol * 4 mol = 89.6 l C2H2

8.
a) C≡CH-CH(CH3)-CH(CH3)-CH3
b) 
M alchina = 72 g/mol
72 g alchina ... 60g C... 12 g H
100 g alchina ...y C.........z H
y = 100 * 60 / 72  = 83.34 % C
z= 100 * 12 / 72 = 16.66 % H

P.S.  ce e scris in paranteze, gen -CH(CH3)-, scrie in jos sau in sus ca ramificatie gen: -CH-
                            |
                           CH3