Question

Ma poate ajuta si pe mine cineva? Dau coroana!​

Answer 1

Răspuns:

2H2 + O2----> 2H2O

3H2+N2--> 2NH3

H2O+ SO3---> H2SO4

CaO+H2O---> Ca(OH)2

CaO +CO2--->CaCO3

BaCl2 + H2SO4---> BaSO4 +2HCL

p=90%calculez masa de sare pura

p=m,px100/m,i---> m,p= 200x90/100kg= 180kg CaCO3

M,CaCO3=(40gCa +12gC+3x16gO)/mol= 100g/mol=100kg/kmol

100kg CaCO3...40KgCa....12kgC.......48KgO

180kg......................x...................y................z

x=72kgCa

y=21,6kgC

z=86,4kgO

-calculez moli sare si moli gaz ,din ecuatia chimica

1mol.............................1mol.....1mol

Zn + H2SO4----> ZnSO4  +   H2

3mol............................x.............y

x= 3molZnSO4=niu

Y=3molH2=niu

-calculez volumul de H2, stiind Vm=22,4 l/mol

V=niuxVm= 3molx22,4l/mol=67,2 l H2

-calculez masa de sare, stiind M,ZnSO4=161g/mol

m=niuxM= 3molx161g/mol=483g ZnSO4

DEDUC MOLI PRODUSI DE REACTIE ,DIN ECUATIA CHIMICA

1mol..................1mol..........1mol

Cu(OH)2-----> CuO +  H2O

3mol................x.............y

x=y=3mol

calculez  masele produsilor ,stiind M,CuO=80g/mol     M,H2O=18g/mol

m= niuxM=3X80g=240gCuO

m,=3x18g= 54gH2O

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