Question

ma poate ajuta si pe mine cineva ?..va rog ​

Answer 1

Explicație:

a)V=150 ml= 0.15 l

c=0.5 mol/l

n= cxV= 0.5x0.15=0.075 Moli AgNO3

M AgNO3 = 170

m= nxM= 0.075x170= 12.75 g AgNO3

b)V= 500 ml= 0.5 l

c= 0.1 mol/l

n=cxV=0.1x 0.5= 0.05 moli BaCl2

M BaCl2= 137+71=208

m= nxM= 0.05x 208=10.4 g BaCl2