Question

Ma poate ajutaa cinevaa la 3??Vaa rog multt de tot

Answer 1

$({2}^{x - 1} - 1)( {3}^{x - 1} - 9) = 0 \\ {2}^{x - 1} - 1 = 0 \\ {2}^{x - 1} = 1 \\ {2}^{x - 1} = {2}^{0} \\ x - 1 = 0 \\ x = 1 \\ \\ {3}^{x - 1} - 9 = 0 \\ {3}^{x - 1} = 9 \\ {3}^{x - 1} = {3}^{2} \\ x - 1 = 2 \\ x = 3$