Question

Mă poate cineva ajuta la acest exercițiu.❤❤​

Answer 1

Răspuns :

$a) \: 9 \frac{3}{4} + 3 \frac{1}{6} = 9 \frac{3}{4} ^{3} + 3 \frac{1}{6} ^{2} = 9 \frac{9}{12} + 3 \frac{2}{12} = 12 \frac{11}{12}$

$b)7 \frac{8}{15} + 8 \frac{17}{20} = 7 \frac{8}{15} ^{4} + 8 \frac{17}{20} ^{3} = 7 \frac{32}{60} + 8 \frac{41}{60} = 15 \frac{73}{60}$

$c)11 \frac{7}{12} + 6 \frac{11}{18} = 11 \frac{7}{12} ^{3} + 6 \frac{11}{18} ^{2} = 11 \frac{21}{36} + 6 \frac{22}{36} = 17 \frac{43}{36}$

$d)7 \frac{3}{8} + 11 \frac{7}{12} = 7 \frac{3}{8} ^{3} + 11 \frac{7}{12} ^{2} = 7 \frac{9}{24} + 11 \frac{14}{24} = 18 \frac{25}{24} = 19 \frac{1}{24}$

$e)3 \frac{5}{9} + 1 \frac{7}{12} = 3 \frac{5}{9} ^{4} + 1 \frac{7}{12} ^{3} = 3 \frac{20}{36} + 1 \frac{21}{36} = 4 \frac{41}{36} = 5 \frac{5}{36}$

$f)3 \frac{1}{7} + \frac{4}{5} = 3 \frac{1}{7} ^{5} + \frac{4}{5} ^{7} = 3 \frac{5}{35} + \frac{28}{35} = 3 \frac{33}{35}$

$g)3 \frac{1}{14} + 2 \frac{4}{21} = 3 \frac{1}{14} ^{3} + 2 \frac{4}{21} ^{2} = 3 \frac{3}{42} + 2 \frac{8}{42} = 5 \frac{11}{42}$

Sper că te-am ajutat