Question

Ma puteti ajuta cu exercitiul 9 dar va rog frumos sa fie tot exercitiul adica pas cu pas cum l-ati rezolvat ofer 44 de puncte

Answer 1

$[2\frac{1}{3} :0,(3)+1,1:( 1\frac{5}{6}-1,(2)]* \frac{5}{11} = \\ \\2 \frac{1}{3}= \frac{7}{3};0,(3)= \frac{3}{9}= \frac{1}{3} ;1,1= \frac{11}{10} ;1,(2)= \frac{12-1}{9} ;1 \frac{5}{6} = \frac{11}{6} \\ \\ ( \frac{7}{3} *3+ \frac{11}{10} :( \frac{11}{6}- \frac{11}{9}))* \frac{5}{11}= \\ \\ 7+ \frac{11}{10} :( \frac{11*3-11*2}{18})* \frac{5}{11} = \\ \\ 7+ \frac{11}{10}:\frac{11}{18}* \frac{5}{11} = \\ \\ 7+ \frac{11}{10}* \frac{18}{11}* \frac{5}{11}=\\ \\ 7+ \frac{18}{22}= \\ \\ \frac{ 7*22+18 }{22}= \fra$

$= \frac{172}{22}$