Question

ma puteti ajuta la acest ex
​

Answer 1

Răspuns:

Explicație pas cu pas:

(1/7)^0 = 1

(4/9)^10 = 2^20/3^20

[(27/8)^3]^2 = (27/8)^6 = 3^18/2^18

________

2^20/3^20 * 3^18/2^18 + 1 = 2^2/3^2 + 1 = 4/9 + 1 = 4/9 + 9/9 = 13/9