Question

ma puteti ajuta la ex 5?
faceti macar doua ca sa inteleg cum se face.

Answer 1

10π/7=π+3π/7
3π/7<3π/6=π/2  =>3π/7<π/2=>
π+3/7*π∈cadran 3.
sin(π+3/7*π)<0 pt  ca  in  cadranul 3sinusul e  negativ
b)sin25/24*π=sin(π+π/24)  π/24>π/2=>π+π/24 apartine  cadranului  3  unde  sinusul  e  negativ
d) sin35π/18=sin(2π-π/18)  π/18<π/2=>
2π-π/18 ∈cadran4 unde  sinusul  e  negativ
sin9π=sin(8π+π)=sinπ=-1