Question

mă puteți ajuta la matematică​

Answer 1

Răspuns:

b)

$= 3 +\frac{22+2}{11} (\frac{125}{100}-\frac{3}{9} )= 3+\frac{24}{11} (\frac{5}{4} -\frac{1}{3} )=$

$= 3+\frac{24}{11} *\frac{5*3-4}{12}=3+\frac{2}{11} *(15-4)=3+2 = 5$

c)

$=(\frac{3+1}{3} +\frac{16-1}{90} )^{2} :\frac{15}{10} -\frac{1}{2} =(\frac{4}{3} +\frac{15}{90} )^{2} *\frac{2}{3} -\frac{1}{2}=$

$=(\frac{4}{3} +\frac{1}{6} )^{2} *\frac{2}{3} -\frac{1}{2}=(\frac{8+1}{6} )^{2} *\frac{2}{3} -\frac{1}{2}=$

$=\frac{3}{2} * \frac{3}{2} *\frac{2}{3} -\frac{1}{2}=\frac{3}{2} -\frac{1}{2}=\frac{2}{2} =1$

Explicație pas cu pas: