Question

Mă puteți ajuta la Subiectul al II lea ex 2?

Answer 1

a=36/(4√3-3√2)-2/(4√2-3√3)-8/(2√3-√2)-16√2/5=
=36(4√3+3√2)/(4√3-3√2)(4√3+3√2)-2(4√2+3√3)/(4√2-3√3)(4√2+3√3)-
-8(2√3+√2)/(2√3-√2)(2√3+√2)-16√2/5=
=36(4√3+3√2)/(48-18)-2(4√2+3√3)/(32-27)-8(2√3+√2)/(12-2)-16√2/5=
=36(4√3+3√2)/30-2(4√2+3√3)/5-8(2√3+√2)/10-16√2/5=
=6(4√3+3√2)/5-2(4√2+3√3)/5-4(2√3+√2)/5-16√2/5=
=(24√3+18√2-8√2-6√3-8√3-4√2-16√2)/5=
=(10√3-10√2)/5=2√3-2√2=2(√3-√2)
a∈(R\Q)