Question

Ma puteti ajuta si la acetata

Answer 1

In primul rand,trebuie sa stii ca la impartirea putetilor,se scad exponentii(daca sunt aceeasi)

$a^{m} \div a^{n} = a^{m - n}$
Acum....la exercitii:

a)
$2 ^{49} \div 2 ^{13} = 2 ^{36}$
b)
$3 ^{103} \div 3^{91} = 3^{12}$
c)
$5 ^{96} \div 5^{96} = 5 ^{0} = 1$
d)
$3 ^{42} \div 3^{12} \div 3 = 3^{29}$
Deoarece,daca o o putere nu are exponent,atinci se deduce ca are exponentul 1.

e)
$7 ^{49} \div 7 ^{15} \div 7 ^{9} = 7 ^{25}$
f)
$7^ {32} \div 7^{5} = 7 ^{27}$
g)
$5^{312} \div 5 ^{56} = 5^{256}$
h)
$71^{32} \div 71^{5} = 71^{27}$
i)
$6^{112} \div 6^{12} \div 6^{43} = 6^{57}$
j)
$8^{91} \div 8^{75} \div 8^{10} = 8^{6}$
k)
$(5^{3})^{23} = 5^{69}$
Deoarece,la orice putere cara la exponent are inmultire,se efectueaza inmultirea la exponent.De exemplu:
$a ^{x} \times a ^{z} = a ^{x \times z}$
l)
$(3^{7})^{21} = 3 ^{147}$
m)
$(25^{1})^{14} = 25^{14} \\ 1 \times 14 = 14$
n)
${(2^{5})^{4}}^{6} = 2^{120}$
o)
${(32^{14})^{5}}^{0} = 32^{0} = 1$

Sper ca te-am ajutat.