Question

Ma puteti ajuta si pe mine rapid cum rezolvarea exercitiul urmator : F(0)+f(1)+f(2)+...+f(69), unde F(x)=x+1? Va rog mult!!!

Answer 1

1+2+3+...+70=70*(70+1)/2=35*71=2485

Answer 2

F(0)=0+1=1
F(1)=1+1=2
F)2)=2+1=3
F(3)=3+1=4
F(4)=4+1=5
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F(69)=69+1=70

F(0)+F(1)+....+F(69)=1+2+3+...+70=70x71:2=2485
1+2+3+....+n=n(n+1):2 asta este formula folosita