Question

Ma puteti ajuta si pe mine?
$\sqrt{2x - 1}$
​

Answer 1

Răspuns:

∫√(2x-1)dx

2x-1=y

2x=1+y

x=(y+1)/2

dx=dy/2

Integrala   devine

F(y)=∫√ydy/2=

1/2∫√ydy=

1/2∫Y^(1/2)dy=

1/2*y^(1/2+!)/(1/2+1)+c=

1/2y^(3/2)*1/(3/2)+c=

y^(3/2)/3+c

Revii   la   substitutie

F(x)=√(2x-1)³/3+c

Explicație pas cu pas: