Question

Ma puteti ajuta : $\frac{(2x-3)^{2} }{6 x^{2} -9x} =$
                        $\frac{ 4x^{2} -9}{ 4x^{2} -12x+9} =$
                        $\frac{ 14x^{2} - 21x}{10x-15} =$
                        $\frac{ 5x^{2} + 13x-6}{5x{2} -7x+2} =$
 Multumesc ! 

Answer 1

= $\frac{ (2x-3)^{2} }{3x(2x-3)} = \frac{2x-3}{3x}$
$\frac{4 x^{2} -9}{4 x^{2} -12x+9} = \frac{(2x-3)(2x+3)}{(2x-3)(2x-3)} = \frac{2x+3}{2x-3}$
$\frac{14 x^{2} -21}{10x-15} = \frac{7x(2x-3)}{5x(2x-3)} = \frac{7}{5}$
$\frac{5 x^{2} +13x-6}{5 x^{2} -7x+2} = \frac{5(x+3)(x- \frac{1}{2} )}{5(x- \frac{1}{2})(x-1) } = \frac{x+3}{x-1}$