Question

Ma puteti ajuta va rog

Answer 1

AB>CD, ducem:
DE⊥AB, E∈AB
CF⊥AB, F∈AB
notam AE=x, ∡A=60 ⇒ ∡ADE=30 ⇒ AD=2x
cu pitagora in ADE
4x^2=x^2+3
x=1, AD=2
∡FCB=135-90=45 ⇒ tr CFB e dr. isoscel ⇒ FB=FC=√3
DC=EF=AB-AE-FB=6-1-√3=5-√3
cu pitagora in CFB
CB^2=CF^2+FB^2=3+3=6
CB=√6
perimetrul P
P=DC+CB+AB+AD=5-√3+√6+6+2
P=13+√3(√2 - 1)