Question

Mă puteți ajuta va rog?!?

Answer 1

$\sqrt{(2x-3)^{2}} \leq1$

$\sqrt{(2x-3)^{2}} =(2x-3)\\ \\ \\2x-3 \leq1\\ \\ 2x\leq1+3\\ \\ 2x\leq4\\ \\ x\leq 2$

x∈(-∞; 2] ∈Z